4=4+z2

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Solution for 4=4+z2 equation: 



4=4+z2

We move all terms to the left:

4-(4+z2)=0

We add all the numbers together, and all the variables

-(+z^2+4)+4=0

We get rid of parentheses

-z^2-4+4=0

We add all the numbers together, and all the variables

-1z^2=0

a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{0}{-2}=0$

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