4=7(6+2z)

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Solution for 4=7(6+2z) equation: 



4=7(6+2z)

We move all terms to the left:

4-(7(6+2z))=0

We add all the numbers together, and all the variables

-(7(2z+6))+4=0



We calculate terms in parentheses: -(7(2z+6)), so:

7(2z+6)

We multiply parentheses

14z+42

Back to the equation:

-(14z+42)



We get rid of parentheses

-14z-42+4=0

We add all the numbers together, and all the variables

-14z-38=0

We move all terms containing z to the left, all other terms to the right

-14z=38

z=38/-14

z=-2+5/7

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