4=7(6c+5)+3

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Solution for 4=7(6c+5)+3 equation: 



4=7(6c+5)+3

We move all terms to the left:

4-(7(6c+5)+3)=0



We calculate terms in parentheses: -(7(6c+5)+3), so:

7(6c+5)+3

We multiply parentheses

42c+35+3

We add all the numbers together, and all the variables

42c+38

Back to the equation:

-(42c+38)



We get rid of parentheses

-42c-38+4=0

We add all the numbers together, and all the variables

-42c-34=0

We move all terms containing c to the left, all other terms to the right

-42c=34

c=34/-42

c=-17/21

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