4=b2/3

Solution for 4=b2/3 equation:

4=b2/3

We move all terms to the left:

4-(b2/3)=0

We add all the numbers together, and all the variables

-(+b2/3)+4=0

We get rid of parentheses

-b2/3+4=0

We multiply all the terms by the denominator


-b2+4*3=0

We add all the numbers together, and all the variables

-1b^2+12=0

a = -1; b = 0; c = +12;
Δ = b2-4ac
Δ = 02-4·(-1)·12
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{3}}{2*-1}=\frac{0-4\sqrt{3}}{-2}
=-\frac{4\sqrt{3}}{-2}
=-\frac{2\sqrt{3}}{-1}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{3}}{2*-1}=\frac{0+4\sqrt{3}}{-2}
=\frac{4\sqrt{3}}{-2}
=\frac{2\sqrt{3}}{-1}
$