4=ln(3/y)

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Solution for 4=ln(3/y) equation: 


D( y )

y = 0

3/y <= 0

y = 0

y = 0

3/y <= 0

3/y <= 0

3*y^-1 <= 0

3*y^-1 <= 0 // : 3

y^-1 <= 0/3

y^-1 <= 0

1/(y^1) <= 0

y <> 0

1/(y^1) <= 0 // * y^2

(y^2)/(y^1) <= 0

y^1 <= 0

y <= 0

y in (-oo:0)

y in (0:+oo)

4 = ln(3/y) // - ln(3/y)

4-ln(3/y) = 0

4-ln(3/y) = 0 // - 4

-ln(3/y) = -4

-ln(3/y) = -4 // * -1

ln(3/y) = ln(e^4)

3/y = e^4

3/y-e^4 = 0

3*y^-1 = e^4 // : 3

y^-1 = (e^4)/3

-1 < 0

1/(y^1) = (e^4)/3 // * y^1

1 = ((e^4)/3)*y^1 // : (e^4)/3

3*e^-4 = y^1

y = 3*e^-4

y = 3*e^-4

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