4=q2+7

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Solution for 4=q2+7 equation: 



4=q2+7

We move all terms to the left:

4-(q2+7)=0

We add all the numbers together, and all the variables

-(+q^2+7)+4=0

We get rid of parentheses

-q^2-7+4=0

We add all the numbers together, and all the variables

-1q^2-3=0

a = -1; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·(-1)·(-3)
Δ = -12
Delta is less than zero, so there is no solution for the equation

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