4=t(4-t)

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Solution for 4=t(4-t) equation:



4=t(4-t)
We move all terms to the left:
4-(t(4-t))=0
We add all the numbers together, and all the variables
-(t(-1t+4))+4=0
We calculate terms in parentheses: -(t(-1t+4)), so:
t(-1t+4)
We multiply parentheses
-1t^2+4t
Back to the equation:
-(-1t^2+4t)
We get rid of parentheses
1t^2-4t+4=0
We add all the numbers together, and all the variables
t^2-4t+4=0
a = 1; b = -4; c = +4;
Δ = b2-4ac
Δ = -42-4·1·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{4}{2}=2$

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