4A+2C=m

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Solution for 4A+2C=m equation: 



4+2=A

We move all terms to the left:

4+2-(A)=0

We add all the numbers together, and all the variables

-1A+6=0

We move all terms containing A to the left, all other terms to the right

-A=-6

A=-6/-1

A=+6

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