4A/4A+12-16/4A+12

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Solution for 4A/4A+12-16/4A+12 equation: 


A in (-oo:+oo)

((4*A)/4)*A-((16/4)*A)+12+12 = 0

((4*A)/4)*A-4*A+12+12 = 0

A^2-4*A+24 = 0

DELTA = (-4)^2-(1*4*24)

DELTA = -80

DELTA < 0

A belongs to the empty set

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