4K+5(k+4)=2(k+4)+k+72

Solution for 4K+5(k+4)=2(k+4)+k+72 equation:

4+5(K+4)=2(K+4)+K+72

We move all terms to the left:

4+5(K+4)-(2(K+4)+K+72)=0

We multiply parentheses

5K-(2(K+4)+K+72)+20+4=0


We calculate terms in parentheses: -(2(K+4)+K+72), so:

2(K+4)+K+72

We add all the numbers together, and all the variables

K+2(K+4)+72

We multiply parentheses

K+2K+8+72

We add all the numbers together, and all the variables

3K+80

Back to the equation:

-(3K+80)


We add all the numbers together, and all the variables

5K-(3K+80)+24=0

We get rid of parentheses

5K-3K-80+24=0

We add all the numbers together, and all the variables

2K-56=0

We move all terms containing K to the left, all other terms to the right

2K=56

K=56/2

K=28