4X(8+3b)=10

Solution for 4X(8+3b)=10 equation:

4X(8+3X)=10

We move all terms to the left:

4X(8+3X)-(10)=0

We add all the numbers together, and all the variables

4X(3X+8)-10=0

We multiply parentheses

12X^2+32X-10=0

a = 12; b = 32; c = -10;
Δ = b2-4ac
Δ = 322-4·12·(-10)
Δ = 1504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1504}=\sqrt{16*94}=\sqrt{16}*\sqrt{94}=4\sqrt{94}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-4\sqrt{94}}{2*12}=\frac{-32-4\sqrt{94}}{24}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+4\sqrt{94}}{2*12}=\frac{-32+4\sqrt{94}}{24}
$