4a(+3)=12+4a

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Solution for 4a(+3)=12+4a equation:



4a(+3)=12+4a
We move all terms to the left:
4a(+3)-(12+4a)=0
We add all the numbers together, and all the variables
4a3-(4a+12)=0
We add all the numbers together, and all the variables
4a^3-(4a+12)=0
We get rid of parentheses
4a^3-4a-12=0
We do not support eapression: a^3

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