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4a(11a+7)=0
We multiply parentheses
44a^2+28a=0
a = 44; b = 28; c = 0;
Δ = b2-4ac
Δ = 282-4·44·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-28}{2*44}=\frac{-56}{88} =-7/11 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+28}{2*44}=\frac{0}{88} =0 $
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