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4a*a-18a-10=0
We add all the numbers together, and all the variables
-18a+4a*a-10=0
Wy multiply elements
4a^2-18a-10=0
a = 4; b = -18; c = -10;
Δ = b2-4ac
Δ = -182-4·4·(-10)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-22}{2*4}=\frac{-4}{8} =-1/2 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+22}{2*4}=\frac{40}{8} =5 $
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