4a+1=2a/8a

Solution for 4a+1=2a/8a equation:

4a+1=2a/8a

We move all terms to the left:

4a+1-(2a/8a)=0


Domain of the equation: 8a)!=0

a!=0/1

a!=0

a∈R


We add all the numbers together, and all the variables

4a-(+2a/8a)+1=0

We get rid of parentheses

4a-2a/8a+1=0

We multiply all the terms by the denominator


4a*8a-2a+1*8a=0

We add all the numbers together, and all the variables

-2a+4a*8a+1*8a=0

Wy multiply elements

32a^2-2a+8a=0

We add all the numbers together, and all the variables

32a^2+6a=0

a = 32; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·32·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*32}=\frac{-12}{64}
=-3/16
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*32}=\frac{0}{64}
=0
$