4a+2+a=3(a-2)

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Solution for 4a+2+a=3(a-2) equation: 



4a+2+a=3(a-2)

We move all terms to the left:

4a+2+a-(3(a-2))=0

We add all the numbers together, and all the variables

5a-(3(a-2))+2=0



We calculate terms in parentheses: -(3(a-2)), so:

3(a-2)

We multiply parentheses

3a-6

Back to the equation:

-(3a-6)



We get rid of parentheses

5a-3a+6+2=0

We add all the numbers together, and all the variables

2a+8=0

We move all terms containing a to the left, all other terms to the right

2a=-8

a=-8/2

a=-4

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