4a+2=3(a-1)+1

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Solution for 4a+2=3(a-1)+1 equation: 



4a+2=3(a-1)+1

We move all terms to the left:

4a+2-(3(a-1)+1)=0



We calculate terms in parentheses: -(3(a-1)+1), so:

3(a-1)+1

We multiply parentheses

3a-3+1

We add all the numbers together, and all the variables

3a-2

Back to the equation:

-(3a-2)



We get rid of parentheses

4a-3a+2+2=0

We add all the numbers together, and all the variables

a+4=0

We move all terms containing a to the left, all other terms to the right

a=-4

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