4a+2a-6-3=a+(7-5-2a)

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Solution for 4a+2a-6-3=a+(7-5-2a) equation: 



4a+2a-6-3=a+(7-5-2a)

We move all terms to the left:

4a+2a-6-3-(a+(7-5-2a))=0

We add all the numbers together, and all the variables

4a+2a-(a+(-2a+2))-6-3=0

We add all the numbers together, and all the variables

6a-(a+(-2a+2))-9=0



We calculate terms in parentheses: -(a+(-2a+2)), so:

a+(-2a+2)

We get rid of parentheses

a-2a+2

We add all the numbers together, and all the variables

-1a+2

Back to the equation:

-(-1a+2)



We get rid of parentheses

6a+1a-2-9=0

We add all the numbers together, and all the variables

7a-11=0

We move all terms containing a to the left, all other terms to the right

7a=11

a=11/7

a=1+4/7

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