4a+5(7a-3)=9(a-5)

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Solution for 4a+5(7a-3)=9(a-5) equation: 



4a+5(7a-3)=9(a-5)

We move all terms to the left:

4a+5(7a-3)-(9(a-5))=0

We multiply parentheses

4a+35a-(9(a-5))-15=0



We calculate terms in parentheses: -(9(a-5)), so:

9(a-5)

We multiply parentheses

9a-45

Back to the equation:

-(9a-45)



We add all the numbers together, and all the variables

39a-(9a-45)-15=0

We get rid of parentheses

39a-9a+45-15=0

We add all the numbers together, and all the variables

30a+30=0

We move all terms containing a to the left, all other terms to the right

30a=-30

a=-30/30

a=-1

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