4a+7(11-a)=68

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Solution for 4a+7(11-a)=68 equation: 



4a+7(11-a)=68

We move all terms to the left:

4a+7(11-a)-(68)=0

We add all the numbers together, and all the variables

4a+7(-1a+11)-68=0

We multiply parentheses

4a-7a+77-68=0

We add all the numbers together, and all the variables

-3a+9=0

We move all terms containing a to the left, all other terms to the right

-3a=-9

a=-9/-3

a=+3

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