4a+7-3(2a+3)=4(3a-4)-7(a-1)

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Solution for 4a+7-3(2a+3)=4(3a-4)-7(a-1) equation: 



4a+7-3(2a+3)=4(3a-4)-7(a-1)

We move all terms to the left:

4a+7-3(2a+3)-(4(3a-4)-7(a-1))=0

We multiply parentheses

4a-6a-(4(3a-4)-7(a-1))-9+7=0



We calculate terms in parentheses: -(4(3a-4)-7(a-1)), so:

4(3a-4)-7(a-1)

We multiply parentheses

12a-7a-16+7

We add all the numbers together, and all the variables

5a-9

Back to the equation:

-(5a-9)



We add all the numbers together, and all the variables

-2a-(5a-9)-2=0

We get rid of parentheses

-2a-5a+9-2=0

We add all the numbers together, and all the variables

-7a+7=0

We move all terms containing a to the left, all other terms to the right

-7a=-7

a=-7/-7

a=1

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