4a+7-a=3(a+2)+1

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Solution for 4a+7-a=3(a+2)+1 equation: 



4a+7-a=3(a+2)+1

We move all terms to the left:

4a+7-a-(3(a+2)+1)=0

We add all the numbers together, and all the variables

3a-(3(a+2)+1)+7=0



We calculate terms in parentheses: -(3(a+2)+1), so:

3(a+2)+1

We multiply parentheses

3a+6+1

We add all the numbers together, and all the variables

3a+7

Back to the equation:

-(3a+7)



We get rid of parentheses

3a-3a-7+7=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0

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