4a-1-3a+2=-3(4+2a)-7(1-a)

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Solution for 4a-1-3a+2=-3(4+2a)-7(1-a) equation:


Simplifying
4a + -1 + -3a + 2 = -3(4 + 2a) + -7(1 + -1a)

Reorder the terms:
-1 + 2 + 4a + -3a = -3(4 + 2a) + -7(1 + -1a)

Combine like terms: -1 + 2 = 1
1 + 4a + -3a = -3(4 + 2a) + -7(1 + -1a)

Combine like terms: 4a + -3a = 1a
1 + 1a = -3(4 + 2a) + -7(1 + -1a)
1 + 1a = (4 * -3 + 2a * -3) + -7(1 + -1a)
1 + 1a = (-12 + -6a) + -7(1 + -1a)
1 + 1a = -12 + -6a + (1 * -7 + -1a * -7)
1 + 1a = -12 + -6a + (-7 + 7a)

Reorder the terms:
1 + 1a = -12 + -7 + -6a + 7a

Combine like terms: -12 + -7 = -19
1 + 1a = -19 + -6a + 7a

Combine like terms: -6a + 7a = 1a
1 + 1a = -19 + 1a

Add '-1a' to each side of the equation.
1 + 1a + -1a = -19 + 1a + -1a

Combine like terms: 1a + -1a = 0
1 + 0 = -19 + 1a + -1a
1 = -19 + 1a + -1a

Combine like terms: 1a + -1a = 0
1 = -19 + 0
1 = -19

Solving
1 = -19

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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