4a-10=3(2-4a)

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Solution for 4a-10=3(2-4a) equation: 



4a-10=3(2-4a)

We move all terms to the left:

4a-10-(3(2-4a))=0

We add all the numbers together, and all the variables

4a-(3(-4a+2))-10=0



We calculate terms in parentheses: -(3(-4a+2)), so:

3(-4a+2)

We multiply parentheses

-12a+6

Back to the equation:

-(-12a+6)



We get rid of parentheses

4a+12a-6-10=0

We add all the numbers together, and all the variables

16a-16=0

We move all terms containing a to the left, all other terms to the right

16a=16

a=16/16

a=1

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