4a-12=3(a+1)+16a+1

Solution for 4a-12=3(a+1)+16a+1 equation:

4a-12=3(a+1)+16a+1

We move all terms to the left:

4a-12-(3(a+1)+16a+1)=0


We calculate terms in parentheses: -(3(a+1)+16a+1), so:

3(a+1)+16a+1

We add all the numbers together, and all the variables

16a+3(a+1)+1

We multiply parentheses

16a+3a+3+1

We add all the numbers together, and all the variables

19a+4

Back to the equation:

-(19a+4)


We get rid of parentheses

4a-19a-4-12=0

We add all the numbers together, and all the variables

-15a-16=0

We move all terms containing a to the left, all other terms to the right

-15a=16

a=16/-15

a=-1+1/15