4a-12=3(a+1)+18a+3

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Solution for 4a-12=3(a+1)+18a+3 equation: 



4a-12=3(a+1)+18a+3

We move all terms to the left:

4a-12-(3(a+1)+18a+3)=0



We calculate terms in parentheses: -(3(a+1)+18a+3), so:

3(a+1)+18a+3

We add all the numbers together, and all the variables

18a+3(a+1)+3

We multiply parentheses

18a+3a+3+3

We add all the numbers together, and all the variables

21a+6

Back to the equation:

-(21a+6)



We get rid of parentheses

4a-21a-6-12=0

We add all the numbers together, and all the variables

-17a-18=0

We move all terms containing a to the left, all other terms to the right

-17a=18

a=18/-17

a=-1+1/17

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