4a-17+6(a-3)=10a+-35

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Solution for 4a-17+6(a-3)=10a+-35 equation:


Simplifying
4a + -17 + 6(a + -3) = 10a + -35

Reorder the terms:
4a + -17 + 6(-3 + a) = 10a + -35
4a + -17 + (-3 * 6 + a * 6) = 10a + -35
4a + -17 + (-18 + 6a) = 10a + -35

Reorder the terms:
-17 + -18 + 4a + 6a = 10a + -35

Combine like terms: -17 + -18 = -35
-35 + 4a + 6a = 10a + -35

Combine like terms: 4a + 6a = 10a
-35 + 10a = 10a + -35

Reorder the terms:
-35 + 10a = -35 + 10a

Add '35' to each side of the equation.
-35 + 35 + 10a = -35 + 35 + 10a

Combine like terms: -35 + 35 = 0
0 + 10a = -35 + 35 + 10a
10a = -35 + 35 + 10a

Combine like terms: -35 + 35 = 0
10a = 0 + 10a
10a = 10a

Add '-10a' to each side of the equation.
10a + -10a = 10a + -10a

Combine like terms: 10a + -10a = 0
0 = 10a + -10a

Combine like terms: 10a + -10a = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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