4a-2(4a-1)=3(a-4)

Solution for 4a-2(4a-1)=3(a-4) equation:

4a-2(4a-1)=3(a-4)

We move all terms to the left:

4a-2(4a-1)-(3(a-4))=0

We multiply parentheses

4a-8a-(3(a-4))+2=0


We calculate terms in parentheses: -(3(a-4)), so:

3(a-4)

We multiply parentheses

3a-12

Back to the equation:

-(3a-12)


We add all the numbers together, and all the variables

-4a-(3a-12)+2=0

We get rid of parentheses

-4a-3a+12+2=0

We add all the numbers together, and all the variables

-7a+14=0

We move all terms containing a to the left, all other terms to the right

-7a=-14

a=-14/-7

a=+2