4a-2(4a-5)=-(4a-8)+2

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Solution for 4a-2(4a-5)=-(4a-8)+2 equation: 



4a-2(4a-5)=-(4a-8)+2

We move all terms to the left:

4a-2(4a-5)-(-(4a-8)+2)=0

We multiply parentheses

4a-8a-(-(4a-8)+2)+10=0



We calculate terms in parentheses: -(-(4a-8)+2), so:

-(4a-8)+2

We get rid of parentheses

-4a+8+2

We add all the numbers together, and all the variables

-4a+10

Back to the equation:

-(-4a+10)



We add all the numbers together, and all the variables

-4a-(-4a+10)+10=0

We get rid of parentheses

-4a+4a-10+10=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0

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