4a-2(a+3)=16

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Solution for 4a-2(a+3)=16 equation: 



4a-2(a+3)=16

We move all terms to the left:

4a-2(a+3)-(16)=0

We multiply parentheses

4a-2a-6-16=0

We add all the numbers together, and all the variables

2a-22=0

We move all terms containing a to the left, all other terms to the right

2a=22

a=22/2

a=11

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