4a-2=4(a+1)+10a+5

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Solution for 4a-2=4(a+1)+10a+5 equation: 



4a-2=4(a+1)+10a+5

We move all terms to the left:

4a-2-(4(a+1)+10a+5)=0



We calculate terms in parentheses: -(4(a+1)+10a+5), so:

4(a+1)+10a+5

We add all the numbers together, and all the variables

10a+4(a+1)+5

We multiply parentheses

10a+4a+4+5

We add all the numbers together, and all the variables

14a+9

Back to the equation:

-(14a+9)



We get rid of parentheses

4a-14a-9-2=0

We add all the numbers together, and all the variables

-10a-11=0

We move all terms containing a to the left, all other terms to the right

-10a=11

a=11/-10

a=-1+1/10

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