4a-2=6(a+1)+11a+6

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Solution for 4a-2=6(a+1)+11a+6 equation: 



4a-2=6(a+1)+11a+6

We move all terms to the left:

4a-2-(6(a+1)+11a+6)=0



We calculate terms in parentheses: -(6(a+1)+11a+6), so:

6(a+1)+11a+6

We add all the numbers together, and all the variables

11a+6(a+1)+6

We multiply parentheses

11a+6a+6+6

We add all the numbers together, and all the variables

17a+12

Back to the equation:

-(17a+12)



We get rid of parentheses

4a-17a-12-2=0

We add all the numbers together, and all the variables

-13a-14=0

We move all terms containing a to the left, all other terms to the right

-13a=14

a=14/-13

a=-1+1/13

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