4a-3(a-2)+6=2(3a-2)

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Solution for 4a-3(a-2)+6=2(3a-2) equation: 



4a-3(a-2)+6=2(3a-2)

We move all terms to the left:

4a-3(a-2)+6-(2(3a-2))=0

We multiply parentheses

4a-3a-(2(3a-2))+6+6=0



We calculate terms in parentheses: -(2(3a-2)), so:

2(3a-2)

We multiply parentheses

6a-4

Back to the equation:

-(6a-4)



We add all the numbers together, and all the variables

a-(6a-4)+12=0

We get rid of parentheses

a-6a+4+12=0

We add all the numbers together, and all the variables

-5a+16=0

We move all terms containing a to the left, all other terms to the right

-5a=-16

a=-16/-5

a=3+1/5

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