4a-3(a-2)=(3a+-2)

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Solution for 4a-3(a-2)=(3a+-2) equation:



4a-3(a-2)=(3a+-2)
We move all terms to the left:
4a-3(a-2)-((3a+-2))=0
We add all the numbers together, and all the variables
4a-3(a-2)-((3a-2))=0
We multiply parentheses
4a-3a-((3a-2))+6=0
We calculate terms in parentheses: -((3a-2)), so:
(3a-2)
We get rid of parentheses
3a-2
Back to the equation:
-(3a-2)
We add all the numbers together, and all the variables
a-(3a-2)+6=0
We get rid of parentheses
a-3a+2+6=0
We add all the numbers together, and all the variables
-2a+8=0
We move all terms containing a to the left, all other terms to the right
-2a=-8
a=-8/-2
a=+4

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