4a-3(a-2)=(3a+-2)

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Solution for 4a-3(a-2)=(3a+-2) equation: 



4a-3(a-2)=(3a+-2)

We move all terms to the left:

4a-3(a-2)-((3a+-2))=0

We add all the numbers together, and all the variables

4a-3(a-2)-((3a-2))=0

We multiply parentheses

4a-3a-((3a-2))+6=0



We calculate terms in parentheses: -((3a-2)), so:

(3a-2)

We get rid of parentheses

3a-2

Back to the equation:

-(3a-2)



We add all the numbers together, and all the variables

a-(3a-2)+6=0

We get rid of parentheses

a-3a+2+6=0

We add all the numbers together, and all the variables

-2a+8=0

We move all terms containing a to the left, all other terms to the right

-2a=-8

a=-8/-2

a=+4

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