4a-3=2(a-3)-4(2a-1)

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Solution for 4a-3=2(a-3)-4(2a-1) equation: 



4a-3=2(a-3)-4(2a-1)

We move all terms to the left:

4a-3-(2(a-3)-4(2a-1))=0



We calculate terms in parentheses: -(2(a-3)-4(2a-1)), so:

2(a-3)-4(2a-1)

We multiply parentheses

2a-8a-6+4

We add all the numbers together, and all the variables

-6a-2

Back to the equation:

-(-6a-2)



We get rid of parentheses

4a+6a+2-3=0

We add all the numbers together, and all the variables

10a-1=0

We move all terms containing a to the left, all other terms to the right

10a=1

a=1/10

a=1/10

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