4a-3=4(a+1)+11a+5

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Solution for 4a-3=4(a+1)+11a+5 equation:



4a-3=4(a+1)+11a+5
We move all terms to the left:
4a-3-(4(a+1)+11a+5)=0
We calculate terms in parentheses: -(4(a+1)+11a+5), so:
4(a+1)+11a+5
We add all the numbers together, and all the variables
11a+4(a+1)+5
We multiply parentheses
11a+4a+4+5
We add all the numbers together, and all the variables
15a+9
Back to the equation:
-(15a+9)
We get rid of parentheses
4a-15a-9-3=0
We add all the numbers together, and all the variables
-11a-12=0
We move all terms containing a to the left, all other terms to the right
-11a=12
a=12/-11
a=-1+1/11

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