4a-4=3(a+1)+8a+3

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Solution for 4a-4=3(a+1)+8a+3 equation: 



4a-4=3(a+1)+8a+3

We move all terms to the left:

4a-4-(3(a+1)+8a+3)=0



We calculate terms in parentheses: -(3(a+1)+8a+3), so:

3(a+1)+8a+3

We add all the numbers together, and all the variables

8a+3(a+1)+3

We multiply parentheses

8a+3a+3+3

We add all the numbers together, and all the variables

11a+6

Back to the equation:

-(11a+6)



We get rid of parentheses

4a-11a-6-4=0

We add all the numbers together, and all the variables

-7a-10=0

We move all terms containing a to the left, all other terms to the right

-7a=10

a=10/-7

a=-1+3/7

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