4a-5=(2a+1)/3

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Solution for 4a-5=(2a+1)/3 equation: 



4a-5=(2a+1)/3

We move all terms to the left:

4a-5-((2a+1)/3)=0

We multiply all the terms by the denominator


4a*3)-((2a+1)-5*3)=0

We add all the numbers together, and all the variables

4a*3)-((2a+1)=0

Wy multiply elements

12a^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{0}{24}=0$

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