4a-5=7-3a+3(2-a)

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Solution for 4a-5=7-3a+3(2-a) equation: 



4a-5=7-3a+3(2-a)

We move all terms to the left:

4a-5-(7-3a+3(2-a))=0

We add all the numbers together, and all the variables

4a-(7-3a+3(-1a+2))-5=0



We calculate terms in parentheses: -(7-3a+3(-1a+2)), so:

7-3a+3(-1a+2)

determiningTheFunctionDomain
-3a+3(-1a+2)+7

We multiply parentheses

-3a-3a+6+7

We add all the numbers together, and all the variables

-6a+13

Back to the equation:

-(-6a+13)



We get rid of parentheses

4a+6a-13-5=0

We add all the numbers together, and all the variables

10a-18=0

We move all terms containing a to the left, all other terms to the right

10a=18

a=18/10

a=1+4/5

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