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4a-a(4-a)=+
We move all terms to the left:
4a-a(4-a)-(+)=0
We add all the numbers together, and all the variables
4a-a(-1a+4)-0=0
We add all the numbers together, and all the variables
4a-a(-1a+4)=0
We multiply parentheses
1a^2+4a-4a=0
We add all the numbers together, and all the variables
a^2=0
a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$a=\frac{-b}{2a}=\frac{0}{2}=0$
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