4a/5(10a-2b)=0

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Solution for 4a/5(10a-2b)=0 equation: 


x in (-oo:+oo)

((4*a)/5)*(10*a-(2*b)) = 0

((4*a)/5)*(10*a-2*b) = 0

4/5*a*(10*a-2*b) = 0

x belongs to the empty set

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