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4a^2+21a+27=0
a = 4; b = 21; c = +27;
Δ = b2-4ac
Δ = 212-4·4·27
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-3}{2*4}=\frac{-24}{8} =-3 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+3}{2*4}=\frac{-18}{8} =-2+1/4 $
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