4a2+3a+36=8a2+3a

Solution for 4a2+3a+36=8a2+3a equation:

4a^2+3a+36=8a^2+3a

We move all terms to the left:

4a^2+3a+36-(8a^2+3a)=0

We get rid of parentheses

4a^2-8a^2+3a-3a+36=0

We add all the numbers together, and all the variables

-4a^2+36=0

a = -4; b = 0; c = +36;
Δ = b2-4ac
Δ = 02-4·(-4)·36
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*-4}=\frac{-24}{-8}
=+3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*-4}=\frac{24}{-8}
=-3
$