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4a^2+811a+8804=0
a = 4; b = 811; c = +8804;
Δ = b2-4ac
Δ = 8112-4·4·8804
Δ = 516857
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(811)-\sqrt{516857}}{2*4}=\frac{-811-\sqrt{516857}}{8} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(811)+\sqrt{516857}}{2*4}=\frac{-811+\sqrt{516857}}{8} $
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