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4a^2+9a+5=0
a = 4; b = 9; c = +5;
Δ = b2-4ac
Δ = 92-4·4·5
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-1}{2*4}=\frac{-10}{8} =-1+1/4 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+1}{2*4}=\frac{-8}{8} =-1 $
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