4a2-8=a

Solution for 4a2-8=a equation:

4a^2-8=a

We move all terms to the left:

4a^2-8-(a)=0

We add all the numbers together, and all the variables

4a^2-1a-8=0

a = 4; b = -1; c = -8;
Δ = b2-4ac
Δ = -12-4·4·(-8)
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{129}}{2*4}=\frac{1-\sqrt{129}}{8}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{129}}{2*4}=\frac{1+\sqrt{129}}{8}
$