4a=(2a+68)

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Solution for 4a=(2a+68) equation: 



4a=(2a+68)

We move all terms to the left:

4a-((2a+68))=0



We calculate terms in parentheses: -((2a+68)), so:

(2a+68)

We get rid of parentheses

2a+68

Back to the equation:

-(2a+68)



We get rid of parentheses

4a-2a-68=0

We add all the numbers together, and all the variables

2a-68=0

We move all terms containing a to the left, all other terms to the right

2a=68

a=68/2

a=34

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