4a=(2a+68)

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Solution for 4a=(2a+68) equation:



4a=(2a+68)
We move all terms to the left:
4a-((2a+68))=0
We calculate terms in parentheses: -((2a+68)), so:
(2a+68)
We get rid of parentheses
2a+68
Back to the equation:
-(2a+68)
We get rid of parentheses
4a-2a-68=0
We add all the numbers together, and all the variables
2a-68=0
We move all terms containing a to the left, all other terms to the right
2a=68
a=68/2
a=34

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