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4b(6b-54)=0
We multiply parentheses
24b^2-216b=0
a = 24; b = -216; c = 0;
Δ = b2-4ac
Δ = -2162-4·24·0
Δ = 46656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{46656}=216$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-216)-216}{2*24}=\frac{0}{48} =0 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-216)+216}{2*24}=\frac{432}{48} =9 $
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