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4b(b+6)2=0
We multiply parentheses
8b^2+48b=0
a = 8; b = 48; c = 0;
Δ = b2-4ac
Δ = 482-4·8·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-48}{2*8}=\frac{-96}{16} =-6 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+48}{2*8}=\frac{0}{16} =0 $
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