4b(cb-zd)=

Solution for 4b(cb-zd)= equation:

Simplifying
4b(cb + -1zd) = 0
(bc * 4b + -1dz * 4b) = 0

Reorder the terms:
(-4bdz + 4b2c) = 0
(-4bdz + 4b2c) = 0

Solving
-4bdz + 4b2c = 0

Solving for variable 'b'.

Factor out the Greatest Common Factor (GCF), '4b'.
4b(-1dz + bc) = 0

Ignore the factor 4.
Subproblem 1
Set the factor 'b' equal to zero and attempt to solve:

Simplifying
b = 0

Solving
b = 0

Move all terms containing b to the left, all other terms to the right.

Simplifying
b = 0
Subproblem 2
Set the factor '(-1dz + bc)' equal to zero and attempt to solve:

Simplifying
-1dz + bc = 0

Reorder the terms:
bc + -1dz = 0

Solving
bc + -1dz = 0

Move all terms containing b to the left, all other terms to the right.

Add 'dz' to each side of the equation.
bc + -1dz + dz = 0 + dz

Combine like terms: -1dz + dz = 0
bc + 0 = 0 + dz
bc = 0 + dz
Remove the zero:
bc = dz

Divide each side by 'c'.
b = c-1dz

Simplifying
b = c-1dz
Solution
b = {0, c-1dz}